Calculating the number of turns on the thread gauge for the thread Size M10 x 1-6H.
The number of turns on thread gauge:
Length of threads: 0.402 ± .015: A length without threads is 0.158- Not given on the picture, and the diameter of countersink is 0.435 / 0.437 x 90°
Thread Size: M10 x 1-6H
I. Minimum of turns
a) Convert the pitch: 1 / 25.4= 0.03937”
b) Minimum of turns:
1) Calculating first the threaded material length when the 0.402” dimension is on the minimum of its tolerance and the 0.158” dimension is in on the maximum of its tolerance:
L1 = (0402 - 0.015) - (0.158+.004)=0.225”
2) Calculating the length without threads.
From the dimension of countersink 0.435 / 0.439. Nominal diameter of countersink is 0.437
From the dimension of the M10-1, the max diameter for internal threads is 10 mm-converted in inch 0.393”.
3) Calculating:
Minimum full length thread=L1-H=0.225 - 0.022= 0.203
Number of turns for the minimum full threads length: 0.203 / 0.0393=5.1653 turns
c) Maximum of turns
Calculating the opposite case when the 0.402 is on the maximum of its tolerance and the 0.158 dimension is on the min of its tolerance:
L 2= (0.402+0.015)-(0.158- 0.004)=0.263”
L max full thread=L2-H= 0.263 - 0.022= .241
Number of turns for the maximum full threads length: 0.241 / 0.0393=6.13 turns
Number of turns: 5.16 turns minimum / 6.13 turns maximum
From the dimension of the M10-1, the max diameter for internal threads is 10 mm-converted in inch 0.393”.
3) Calculating:
Minimum full length thread=L1-H=0.225 - 0.022= 0.203
Number of turns for the minimum full threads length: 0.203 / 0.0393=5.1653 turns
c) Maximum of turns
Calculating the opposite case when the 0.402 is on the maximum of its tolerance and the 0.158 dimension is on the min of its tolerance:
L 2= (0.402+0.015)-(0.158- 0.004)=0.263”
L max full thread=L2-H= 0.263 - 0.022= .241
Number of turns for the maximum full threads length: 0.241 / 0.0393=6.13 turns
Number of turns: 5.16 turns minimum / 6.13 turns maximum
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